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javascript: how to work by 'property reference'

开发者 https://www.devze.com 2023-02-05 18:10 出处:网络
i have this question: I have made a \"generic\" object to threat with json models. I need to pass by reference a property of this model by his \'string name\'.

i have this question: I have made a "generic" object to threat with json models. I need to pass by reference a property of this model by his 'string name'. The problem is that the property is a value type not an object type so i lose the reference and the changes will not be propagated.

Example:

function Manager(json){this.JsonModel = json;}
Manager.prototype.Increment = function(propertyName){
  this.JsonModel[propertyName]++;
}

var manager = new Manager({"a" : 5});
alert(manager.Increment("a"));

ok it work well but what about this situation:?

var manager = new Manager({"a" : {"a1" : 5 }});
alert(manager.Increment("a.a1"));

h开发者_如何学Cow can i do that in better way?

Tnx a lot to all.


This is the "Evil" solution, but it works :)

function A(json) {
    this.Data = json;
}

A.prototype.inc = function(prop) {
    //OMG, It's eval!!! NOOO
    eval("this.Data." + prop + "++");
}

var p = new A({a : { c : 5 }, b: 2});

p.inc("b");
alert(p.Data.b);
p.inc("a.c");
alert(p.Data.a.c);


OK, this is the not so evil solution and it works too, at least for the scenario that you have here...

function A(json)
{
    this.Data = json;
}

A.prototype.inc = function(prop)
{
    var d = this.Data;

    var s = prop.split(".");

    for (var i=0; i < s.length - 1; i++)
    {
        d = d[s[i]];
    }

    d[s[i]]++;
}

    var p = new A({ a : { b : { c : 5 }}});

p.inc("a.b.c");

alert(p.Data.a.b.c);


This is my solution:

Usages:

alert(CommonUt.GetValueProperty({"Mammal" :{"Dog": {"Value" : 5}}}, "Mammal.Dog.Value")); CommonUt.SetValueProperty({"Mammal" :{"Dog": {"Value" : 5}}}, "Mammal.Dog.Value", 6);

var CommonUt = {

/***
 * Check if the propertyName is present in obj.
 * PropertyName can be a string with 'dot' separator for deepest property
 * Ex: ContainProperty(json, "Mammal.Dog");
 * @param obj The object where search the property
 * @param propertyName {string} the name of the property
 */
ContainProperty : function(obj, propertyName) {
    if (!IsNotNullObject(obj)) {
        return false
    }
    if (!IsNotEmptyString(propertyName)) {
        throw new Error("I cannot check for an empty property name.");
    }
    if (propertyName.indexOf('.') === -1) {
        return (propertyName in obj);
    }
    var refObj = obj;
    var founded = true;
    $.each(propertyName.split('.'), function(i, item) {
        if (!(item in refObj)) {
            founded = false;
            return false;
        }
        refObj = refObj[item];
    });
    return founded;
},

/***
 * Get the value of a property (or sub-property)
 * WARN: if the value of the property is 'value-type' any changes will not be propagated!
 * @param obj {object}
 * @param propertyName {string} Property name. For 'deep' property split by dots: Mammal.Dog
 */
GetValueProperty : function(obj, propertyName) {
    if (!CommonUt.ContainProperty(obj, propertyName)) {
        throw new Error("I cannot retrieve the property reference if the property doesen't exists!");
    }
    if (propertyName.indexOf('.') === -1) {
        return obj[propertyName];
    }
    var refObj = obj;
    $.each(propertyName.split('.'), function(i, item) {
        refObj = refObj[item];
    });
    return refObj;
},

/***
 * To threat with value properties, use this 
 * @param obj
 * @param propertyName
 * @param value
 */
SetValueProperty : function(obj, propertyName, value) {
    if (!CommonUt.ContainProperty(obj, propertyName)) {
        throw new Error("I cannot retrieve the property reference if the property doesen't exists!");
    }
    if (propertyName.indexOf('.') === -1) {
        obj[propertyName] = value;
        return;
    }
    var refObj = obj;
    var slices = propertyName.split('.');
    for (var i = 0; i < (slices.length - 1); i++) {
        refObj = refObj[slices[i]];
    }
    refObj[slices[slices.length-1]] = value;
}

};

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