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C extension: <? and >? operators
Take a look at the top answer (by sclo) to problem D of this Google Code Jam. It's C++ code, it must have compiled, and it contains statements such as this one:
double& ret = F[mask][cur][b];
if(j==cur) {
ret<?=f(tmp,j,b||bad[i])+M[cur][i]; // WTF is <?= ???
}
This doesn't compile in my Visual Studio 2008. What does the <?=
开发者_开发问答mean?
It's a gcc extension: C extension: <? and >? operators
Recent manuals say:
The G++ minimum and maximum operators (‘
<?
’ and ‘>?
’) and their compound forms (‘<?=
’) and ‘>?=
’) have been deprecated and are now removed from G++. Code using these operators should be modified to usestd::min
andstd::max
instead...
It's simply not valid C++. <
Might be less than, an open angle bracket for a template argument list, or the start of a digraph however non of those can be followed by ?
, then =
.
It's a now deprecated g++ extension to the c++ language.
a <? b
is the minimum, returning the smaller of the numeric values a and b;
a >? b
is the maximum, returning the larger of the numeric values a and b.
There are also compound versions
<?=
and
>?=
that do assignment as well.
It doesn't compile also with GCC, and I've never heard of an operator <?=
.
Anyway I would hazard a guess that a<?=b
could have a semantics like: a = (a<b) ? b : a
, but again, this is just a guess.
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