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Delete N number of old records from table in mysql

开发者 https://www.devze.com 2023-02-05 09:41 出处:网络
I have a LoginTime table like this: id | user_id | datetime 1|1| 2011-01-19 18:51:01 2|1| 2011-01-19 18:51:02

I have a LoginTime table like this:

id | user_id | datetime
1  |   1     | 2011-01-19 18:51:01
2  |   1     | 2011-01-19 18:51:02  
3  |   1     | 2011-0开发者_开发知识库1-19 18:51:03  
4  |   1     | 2011-01-19 18:51:04  
5  |   1     | 2011-01-19 18:51:05  
6  |   1     | 2011-01-19 18:51:06  
7  |   1     | 2011-01-19 18:51:07  
8  |   1     | 2011-01-19 18:51:08  
9  |   1     | 2011-01-19 18:51:09  
10 |   2     | 2011-01-19 18:51:10  

I want to keep only 5 latest(by 'datetime' column) records and delete all previous records where user_id=1

Is it possible to achieve this with one mysql query ?


DELETE 
FROM LoginTime 
WHERE user_id = 1 
ORDER BY datetime ASC 
LIMIT 5


I believe this will work...

DELETE FROM LoginTime WHERE id IN (
     SELECT id
     WHERE user_id = 1
     ORDER BY datetime DESC
     LIMIT 0, 5
)


delete LoginTime
from 
  LoginTime
left join
  (
    select id
    from LoginTime
    where user_id=1
    order by `datetime` desc
    limit 5
  ) as not_to_delete
on LoginTime.id=not_to_delete.id
where
  not_to_delete.id is null;

PS: please don't use CamelCase for table name, and avoid using reserved keywords for the column name


delete LoginTime
from 
  LoginTime

left join
  (
    select id
    from LoginTime
    where user_id=1
    order by datetime desc
    limit 5
  ) as not_to_delete
on LoginTime.id=not_to_delete.id

left join
  (
    select id
    from LoginTime
    where user_id=1
  ) as existance
on LoginTime.id=existance.id

where
  not_to_delete.id is null and existance.id is not null;
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