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How do I check if a number evaluates to infinity?

开发者 https://www.devze.com 2023-02-05 02:37 出处:网络
I have a series of Javascript calculations that (only under IE) show Infinity depending on user choices.

I have a series of Javascript calculations that (only under IE) show Infinity depending on user choices.

How does one 开发者_如何学JAVAstop the word Infinity appearing and for example, show 0.0 instead?


if (result == Number.POSITIVE_INFINITY || result == Number.NEGATIVE_INFINITY)
{
    // ...
}

You could possibly use the isFinite function instead, depending on how you want to treat NaN. isFinite returns false if your number is POSITIVE_INFINITY, NEGATIVE_INFINITY or NaN.

if (isFinite(result))
{
    // ...
}


In ES6, The Number.isFinite() method determines whether the passed value is a finite number.

Number.isFinite(Infinity);  // false
Number.isFinite(NaN);       // false
Number.isFinite(-Infinity); // false

Number.isFinite(0);         // true
Number.isFinite(2e64);      // true


A simple n === n+1 or n === n/0 works:

function isInfinite(n) {
  return n === n/0;
}

Be aware that the native isFinite() coerces inputs to numbers. isFinite([]) and isFinite(null) are both true for example.


Perform the plain ol’ comparison:

(number === Infinity || number === -Infinity)

or to save several characters:

Math.abs(number) === Infinity

Why to use this

  1. !(Number.isFinite(number)) breaks on NaN inputs.
  2. Number.POSITIVE_INFINITY and Number.NEGATIVE_INFINITY can be redefined; they are configurable.
  3. Infinity and -Infinity are read-only in the strict mode.
  4. It is the shortest solution.


Actually n === n + 1 will work for numbers bigger than 51 bit, e.g.

1e16 + 1 === 1e16; // true
1e16 === Infinity; // false


I like to use Lodash for a variety of defensive coding reasons as well as readability. ES6 Number.isFinite is great and does not have issues with non-numeric values, but if ES6 isn't possible, you already have lodash, or want briefer code: _.isFinite

_.isFinite(Infinity); // false
_.isFinite(NaN); // false
_.isFinite(-Infinity); // false

_.isFinite(null); // false
_.isFinite(3); // true
_.isFinite('3'); // true


I've ran into a scenario that required me to check if the value is of the NaN or Infinity type but pass strings as valid results. Because many text strings will produce false-positive NaN, I've made a simple solution to circumvent that:

  const testInput = input => input + "" === "NaN" || input + "" === "Infinity";

The above code converts values to strings and checks whether they are strictly equal to NaN or Infinity (you'll need to add another case for negative infinity).

So:

testInput(1/0); // true
testInput(parseInt("String")); // true
testInput("String"); // false


You can use isFinite in window, isFinite(123):

You can write a function like:

function isInfinite(num) {
 return !isFinite(num);
}

And use like:

isInfinite(null); //false
isInfinite(1); //false
isInfinite(0); //false
isInfinite(0.00); //false
isInfinite(NaN); //true
isInfinite(-1.797693134862316E+308); //true
isInfinite(Infinity); //true
isInfinite(-Infinity); //true
isInfinite(+Infinity); //true
isInfinite(undefined); //true

You can also Number.isFinite which also check if the value is Number too and is more accurate for checking undefined and null etc...

Or you can polyfill it like this:

Number.isFinite = Number.isFinite || function(value) {
  return typeof value === 'number' && isFinite(value);
}
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