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How to select a node in Tree based on XML node property?

开发者 https://www.devze.com 2023-02-05 00:44 出处:网络
I have a tree im my mxml that uses a XMLListCo开发者_如何学JAVAllection as dataProvider. It´s XML is like:

I have a tree im my mxml that uses a XMLListCo开发者_如何学JAVAllection as dataProvider. It´s XML is like:

    <list>
      <conta nome="Plano de Contas" id="1">
        <conta nome="Creditos" id="2" />
          <conta nome="Vendas" id="4" />
          <conta nome="Juros" id="5" />
        <conta nome="Debitos" id="3" />
      </conta>
    </list>

How can I make the node for, say, id==4 visible AND selected?

Thank you.


var xml:XML =
<list>
  <conta nome="Plano de Contas" id="1">
    <conta nome="Creditos" id="2" />
      <conta nome="Vendas" id="4" />
      <conta nome="Juros" id="5" />
    <conta nome="Debitos" id="3" />
  </conta>
</list>;

//find node conta with id=4 using xml selectors
var node:XML = xml.descendants("conta").(@id == 4)[0];
tree.selectedItem = node;

You might need to open node parents if they are not, mx:Tree might not do this automatically.


For selection you can use, this.myTree.selectedIndex=4, that done, it should become visible automatically.

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