my page content is big and there is a link. when user mouse over the link then a div is popup but when i scroll the browser window then div position should change when it appears. how to write and show the div by jquery in such a way that d开发者_如何学Goiv should open and adjust position when user drag the scroll bar top & down. please advice how to do it very simply.
hey, you can use pure CSS e.g. position:fixed;top:30px;left:30px;z-index:100;
second jQuery solution:
CSS:
<style type="text/css">
#mainmenu{position:absolute;left:30px;top:30px;z-index:100;}
#content{height:2000px;}
</style>
jQuery
<script type="text/javascript">
$(function(){
$(window).scroll(function(){
$('#mainmenu').animate({top:$(window).scrollTop()+30},500);
});
});
</script>
HTML:
<div id="mainmenu">
<ul>
<li><a href="">link 1</a></li>
<li><a href="">link 2</a></li>
<li><a href="">link 3</a></li>
<li><a href="">link 4</a></li>
</ul>
</div>
<div id="content">
</div>
Cheers
G.
You could use jquery's scroll to track for when the user scrolls ie:
$(window).scroll(function () {
$("#divId").offset({ left: left, top: top});
});
EDIT:
Also have a look at this blog entry
$(window).scroll(function () {
var windowWidth = document.documentElement.clientWidth;
var windowHeight = document.documentElement.clientHeight;
var divWidth = windowWidth * 0.7;
var divHeight = windowHeight * 0.7;
$("#divPopup").width(divWidth);
$("#divPopup").height(divHeight);
var popupWidth = $("#divPopup").width();
var popupHeight = $("#divPopup").height();
$("#divPopup").css({
"position": "absolute",
"top": (windowHeight / 2 - popupHeight / 2) + $(window).scrollTop(),
"left": windowWidth / 2 - popupWidth / 2
});
});
精彩评论