How to find instance of a bound method in Python?

>>> class A(object):  
...         def some(self):  
...                 pass  
...  
>>> a=A()  
>>> a.some  
&l开发者_JAVA百科t;bound method A.some of <__main__.A object at 0x7f0d6fb9c090>>

IOW, I need to get access to "a" after being handed over only "a.some".

---

Starting python 2.6 you can use special attribute __self__:

>>> a.some.__self__ is a
True

im_self is phased out in py3k.

For details, see the inspect module in the Python Standard Library.

---

>>> class A(object):
...   def some(self):
...     pass
...
>>> a = A()
>>> a
<__main__.A object at 0x7fa9b965f410>
>>> a.some
<bound method A.some of <__main__.A object at 0x7fa9b965f410>>
>>> dir(a.some)
['__call__', '__class__', '__cmp__', '__delattr__', '__doc__', '__format__', '__func__', '__get__', '__getattribute__', '__hash__', '__init__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__self__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', 'im_class', 'im_func', 'im_self']
>>> a.some.im_self
<__main__.A object at 0x7fa9b965f410>

---

Try following code and see, if it helps you:

a.some.im_self

---

You want something like this I guess:

>>> a = A()
>>> m = a.some
>>> another_obj = m.im_self
>>> another_obj
<__main__.A object at 0x0000000002818320>

im_self is the class instance object.