WordPress - How to remove parent taxonomy name from the title generated by wp_title()?

I have a custom taxonomy "Portfolio Categories", and a few these categories say "Cloth", "Shoes", ...

When open some category page, i want the title to be like 'Site Name | Cloth', but with wp_title(), it becomes 'Site Name | Portfolio Categories | Cloth'

How do i remove the "Portfolio Categories" fr开发者_开发技巧om the title?

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simply use the wp_title filter (some info here: http://adambrown.info/p/wp_hooks/hook/wp_title)

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Are you saying you have a hierarchical custom taxonomy and you want the second-level taxonomies to have URLs which don't include their parent's name in them?

If you are saying that then, as far as I understand it, that's not possible - because it's hierarchical. If you want to have a url such as:

http://yourdomain.com/cloth/

then you'll need a non-hierarchical taxonomy.

The alternative is to set up a custom page template and create a page called 'Cloth' and select your new template for this page. In your template you would create a loop which output only the posts that are in this custom taxonomy.

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Try putting this in your header.php:

<title><?php
  global $page, $paged, $post;
  if (is_tax()) {
    $term = get_term_by( 'slug', get_query_var( 'term' ), get_query_var( 'taxonomy' ) );
    $term_title = $term->name;
    echo "$term_title | ";
  } else {
    wp_title( '|', true, 'right' );
  }

  // Add the blog name.
  bloginfo( 'name' );

  // Add the blog description for the home/front page.
  $site_description = get_bloginfo( 'description', 'display' );
  if ( $site_description && ( is_home() || is_front_page() ) )
    echo " | $site_description";

  // Add a page number if necessary:
  if ( $paged >= 2 || $page >= 2 )
    echo ' | ' . sprintf( __( 'Page %s', 'twentyten' ), max( $paged, $page ) );

  ?></title>