org.hibernate.PropertyAccessException - How to get a null value out of database?

Here is the exception:

org.hibernate.PropertyAccessException: Null value was assigned to a property of primitive type setter of com.FOO.hibernate.Tccl.MIN.

I found that this exception happen when i try to get the null value from MIN column. There're some solutions for this issue:

• Set "NULL" (a string) for MIN column
• Set default value, like 0 or 0.0.

But MIN column has the INT type and 0 or 0.0 is such a value in my case.

Here is my code:

        String HQL_QUERY = "from Tccl tccl";
        Query query = session.createQuery(HQL_QUERY);
        List<Tccl> 开发者_JS百科list = query.list();
        for(Tccl tccl : list){
               //fetch data here
        }

The exception happen at:

 List<Tccl> list = query.list();

Are there any solutions for this?

---

You should use the Object type Integer for your field "MIN" of the Tccl class instead of the primitive type int. This will allow null values.