I've got a dictionary like
dic = {'s_good': 23, 's_bad': 39, 'good_s': 34}
I want to remove all the keys that begins with 's_'
So in this case first two w开发者_Python百科ill be removed.
Is there any efficient way to do so?
This should do it:
for k in dic.keys():
if k.startswith('s_'):
dic.pop(k)
for k in dic.keys():
if k.startswith('s_'):
del dic[k]
* EDIT *
now in python 3 , years after the original answer, keys()
returns a view into the dict so you can't change the dict size.
One of the most elegant solutions is a copy of the keys:
for k in list(dic.keys()):
if k.startswith('s_'):
del dic[k]
With python 3 to avoid the error:
RuntimeError: dictionary changed size during iteration
This should do it:
list_keys = list(dic.keys())
for k in list_keys:
if k.startswith('s_'):
dic.pop(k)
You can use a dictionary comprehension:
dic = {k: v for k, v in dic.items() if not k.startswith("s_")}
Note that this creates a new dictionary (which you then assign back to the dic
variable) rather than mutating the existing dictionary.
How about something like this:
dic = dict( [(x,y) for x,y in dic.items() if not x.startswith('s_')] )
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