Nsnumber out of scope problem

I am trying to make NSNumber *percent to get the integer value percentint but it keeps making it out of scope.. The Nslog logs are like this:

The value of integer num is 4

The value of integer num is with NsNumber 78910432

My code is this:

In my header file:

int percentint;  
NSNumber *percent;
@property(nonatomic,re开发者_如何学Pythontain) NSNumber *percent; //tried without using this too

In my .m file:

@synthesize percent; //tried without using this too

percentint=4;

NSLog(@"The value of integer num is %i", percentint);

percent= [NSNumber numberWithInt:percentint];

percent= [[NSNumber alloc] initWithInt:percentint]; //tried without using this too. 

[percent autorelease]; //tried without using this too.

NSLog(@"The value of integer num is with NsNumber %i", percent);

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Try:

percentint=4;
NSLog(@"The value of integer num is %i", percentint);
self.percent= [NSNumber numberWithInt:percentint];
NSLog(@"The value of integer num is in array %@", self.percent);
NSLog(@"The value of integer num is in array %d", [self.percent intValue]);

leaving the @synthesize percent; in.

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User @Felz is correct. in order to get the value of a NSNumber, you must retrieve it with a method call:

int percentInt = 95;
NSNumber *percent = [NSNumber numberWithInt:percentInt];
int myint = [percent intValue];

What you did instead, was print out the pointer address for percent

NSLog(@"Percent Value: %d",[percent intValue]);
NSLog(@"Percent Address: 0x%X",percent);

Remember that NSNumber *percent means percent is a pointer not a value.

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Like the other user insinuated, NSNumber is not an integer as you are trying to call it in the last NSLog. to get the int value out of a NSNumber, use [percent intValue].

Another side note: you don't need to initialize percent twice. The first call numberWithInt: is like doing an alloc/init/release.

Also, never release an object before you are done with it.