I am wondering what the proper way to go about downloading the image from this RUL would be: http://www.hidemyass.com/proxy-list/img/port/7018246/1
开发者_如何学JAVAThe way I tried downloading it, leaves the file in an unknown format. Current code snippet I tested out is:
public void download(def address) {
def file = new FileOutputStream(address.tokenize("/")[-1])
def out = new BufferedOutputStream(file)
out << new URL(address).openStream()
out.close()
}
Does this work? I believe it should:
public void download(def address) {
new File("${address.tokenize('/')[-1]}.png").withOutputStream { out ->
out << new URL(address).openStream()
}
}
Thanks Tim, I also found your answer very helpful, just small note: Looks like you haven't closed URL stream. I'm just starting with Groovy, and I've heard that it close steams when exit from closure so we can change code like that:
public void download(def address) {
new File("${address.tokenize('/')[-1]}.png").withOutputStream { out ->
new URL(address).withInputStream { from -> out << from; }
}
}
You can get image type from their content type - URLConnection.getContentType() or from byte array:
content="http://www.google.ru/images/logo.png".toURL().getBytes()
ext=URLConnection.guessContentTypeFromStream(new ByteArrayInputStream(content)).replaceFirst("^image/","")
new File("logo."+ext).setBytes(content)
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