I have a function that uses basic_istream as an argument, and I have a std::string with the data I need to开发者_如何学运维 pass it. How do I do that?
You can put the string data into a stream:
std::string x;
std::stringstream ss(x); // put string into stream
function_taking_stream(ss);
A full working example showing how to parse a json string using boost property_tree:
#include <iostream>
#include <string>
#include <boost/property_tree/ptree.hpp>
#include <boost/property_tree/json_parser.hpp>
using boost::property_tree::ptree;
int main ()
{
std::string jsonString ("{ \"my key\": \"my value\" }");
ptree pt;
std::stringstream ss(jsonString);
read_json(ss, pt);
std::cout << pt.get<std::string>("my key") << std::endl;
return 0;
}
I have a function that uses basic_istream as an argument...
So I'm assuming you have a function that accepts a variable of a type specialized from the basic_istream template.
...and I have a std::string with the data I need to pass it.
So I'm assuming you want to feed this data into the istream argument.
How do I do that?
You don't. You can't feed output to an input stream!
I think the OP means he has a basic_istream<E>
to read from and wants to read to a std::string
, not to a std::basic_string<E>
.
You should probably write to the basic_string first then convert that to a std::string. If you want to ensure the conversion is correct you probably want a proper UTF-8 to UTF-16 converter.
If you know you are dealing with only ASCII bytes you can do something like:
std::basic_string<E> strTemp;
is >> strTemp;
std::string str( strTemp.begin(), strTemp.end() );
If you have a basic_ostream<E>
you can similarly first construct a basic_string<E>
from your std::string and then write that to the stream.
You can "specialise" your template function so that if E happens to be char the conversion is quick. For that purpose you can input the two strings as non-const references and the specialised version could just "swap".
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