PHP Validate string characters are UK or US Keyboard characters

What is the easiest or best way in PHP to validate true or false that a string开发者_开发知识库 only contains characters that can be typed using a standard US or UK keyboard with the keyboard language set to UK or US English?

To be a little more specific, I mean using a single key depression with or without using the shift key.

I think the characters are the following. 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz~`!@#$%^&*()_-+={[}]|\:;"'<,>.?/£ and Space

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You can cover every ASCII character by [ -~] (i.e. range from space to tilde). Then just add £ too and there you go (you might need to add other characters as well, such as ± and §, but for that, have a look at the US and UK keyboard layouts).

Something like:

if(preg_match('#^[ -~£±§]*$#', $string)) {
    // valid
}

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The following regular expression may be of use for you:

/^([a-zA-Z0-9!"#$%&'()*+,\-.\/:;<=>?@[\\\]^_`{|}~\t ])*$/m

Use this as:

$result = (bool)preg_match('/^([a-zA-Z0-9!"#$%&\'()*+,\-.\/:;<=>?@[\\\]^_`{|}~\t ])*$/m', $input);

Or create a reusable function from this code:

function testUsUkKeyboard($input) 
{
    return (bool)preg_match('/^([a-zA-Z0-9!"#$%&\'()*+,\-.\/:;<=>?@[\\\]^_`{|}~\t ])*$/m', $input);
}

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The easier way to check is to check if chars exist rather then they do not, so first you would need a list of chars that do not exists, you can get these from the ascii range 128 - 255 where as 0 - 127 is the regular key set.

Tio create the invalid array uou can do:

$chars = range(128,255);

The above array would contain all the chars in the table below:

then you should check agains the string in question, people say use regex, but i dont really think thats needed

$string = "testing a plain string";

for($s=0;$s<strlen($string);$s++)
{
    if(in_array(ord($string[$s]),$chars))
    {
        //Invalid
    }
}