开发者

jquery recognizing later inserted html

开发者 https://www.devze.com 2023-02-03 05:51 出处:网络
Hello guys i have this script: function getList(){ $.ajax({ type: \"POST\", url: \"listaPogovorki.php\", success: function(msg){

Hello guys i have this script:

function getList(){
$.ajax({
   type: "POST",
   url: "listaPogovorki.php",
   success: function(msg){
   $("#listaPogovorki").html(msg);
 }});

}

getList();

with this i call this php script:

<table>
<col id="td1"/>
<col id="td2"/>
<col id="td3"/>
<col id="td4"/>
<tr>
<td >#ID</td>
<td >Pogovorka</td>
<td >Avtor</td>
<td >Izmeni</td>
</tr>
<?php $result = mysql_query("SELECT * FROM $table");

while($row = mysql_fetch_array($result))
  {
  ?>
  <tr>
  <td><?php echo $row['id'];?></td>
  <td><?php echo $row['pogovorka'];?></td>
  <td><?php echo $row['avtor'] ?></td>
  <td><img class="editImage" src="images/icon_pencil.png" width="16px" height="16px" alt="<?php echo $row['id'];?>"></td>
  </tr>
  <?php } 
  mysql_close($con);
  ?>

</tabl开发者_JAVA百科e>

now the problem is that the script doesn't recognize the html returned from the php script so i can't make clicking on the images(from php script) to fire some code. For example if i make:

$(".editImage").click .... 

it wont work.

How can i make this work?


You want to use the live function:

$('.editImage').live('click', ....);

Or use another element as an event delegate.


The output is not recognised because the html you have returned is not part of the original dom before the script was called.

Have a look at bind or live with jquery


You could place the $(".editImage").click inside the AJAX success callback after updating the DOM with the new HTML or use the .live() method:

$('.editImage').live('click', function() {
    ...
});


This is what the .live function is for - it binds even to elements that don't exist yet.

$(".editImage").live("click", function() {});

http://api.jquery.com/live/

0

精彩评论

暂无评论...
验证码 换一张
取 消