I can not solve this problem. When I compile ,the compiler gives me an error because of free func

#include <stdio.h&开发者_开发百科gt;
#include <stdlib.h>


void copyint(char *i,char** temp);
int main()
{
    char* a="00313";
    char* temp;
    int inte;
    temp=(char*)malloc(sizeof(char));

    copyint(a,&temp);

    inte=atoi(temp);
    printf("%s\n",temp);
    system("PAUSE");
    free(temp);
}

void copyint(char *i,char** temp)
{
    *temp=i;
}

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no question so point what is wrong on the first sight: - copyint copies single char into pointed memory. so what is being done: temp value is '0', random, random....

'0',random random is parsed by atoi - undefined since we don't know what under this pointer resides. and then it's printed out...

use strlen malloc strcpy sequence instead

Edit: it doesn't compile since you pass a (char*) into function which accepts (char). (copyint(a,&temp);)

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Your code is bugged.

temp = malloc(sizeof(char));

allocates one byte to temp.

copyint(a, &temp);

passes the ADDRESS of "temp". "temp" then gets overwritten so it no longer points to the allocated memory. Hence it cannot be freed.

Secondly, the first parameter to copyint is a char but you are passing a char *. Lastly, what on earth are you doing with atoi()?

I think you need to find out what copyint() actually does. What are you trying to do anyway? of

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You are allocationg memory for 1 char, but copying 4 bytes to that pointer in copyint function.

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Even if the question is not so clear, I believe that including malloc.h will solve the problem, at least if you're using a VC compiler.
HTH