I'd like开发者_开发技巧 to get a list of files that apply to a regex that i have. I guess i should use os.walk, but how can i use it with regex?
Thanks.
I'm not aware of anything in the stdlib implementing this, but it is not hard to code:
import os, os.path
def iter_matching(dirpath, regexp):
"""Generator yielding all files under `dirpath` whose absolute path
matches the regular expression `regexp`.
Usage:
>>> for filename in iter_matching('/', r'/home.*\.bak'):
.... # do something
"""
for dir_, dirnames, filenames in os.walk(dirpath):
for filename in filenames:
abspath = os.path.join(dir_, filename)
if regexp.match(abspath):
yield abspath
Or the more general:
import os, os.path
def filter_filenames(dirpath, predicate):
"""Usage:
>>> for filename in filter_filenames('/', re.compile(r'/home.*\.bak').match):
.... # do something
"""
for dir_, dirnames, filenames in os.walk(dirpath):
for filename in filenames:
abspath = os.path.join(dir_, filename)
if predicate(abspath):
yield abspath
If your regex can be translated into a shell expression such as foo/*.txt
then you can use glob
.
>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']
精彩评论