Is开发者_如何学Python there a built-in function to trim leading and trailing whitespace such that trim(" hello world ") eq "hello world"?
Here's one approach using a regular expression:
$string =~ s/^\s+|\s+$//g ;     # remove both leading and trailing whitespace
Perl 6 will include a trim function:
$string .= trim;
Source: Wikipedia
This is available in String::Util with the trim method:
Editor's note: String::Util is not a core module, but you can install it from CPAN with [sudo] cpan String::Util.
use String::Util 'trim';
my $str = "  hello  ";
$str = trim($str);
print "string is now: '$str'\n";
prints:
string is now 'hello'
However it is easy enough to do yourself:
$str =~ s/^\s+//;
$str =~ s/\s+$//;
There's no built-in trim function, but you can easily implement your own using a simple substitution:
sub trim {
    (my $s = $_[0]) =~ s/^\s+|\s+$//g;
    return $s;
}
or using non-destructive substitution in Perl 5.14 and later:
sub trim {
   return $_[0] =~ s/^\s+|\s+$//rg;
}
According to this perlmonk's thread:
$string =~ s/^\s+|\s+$//g;
Complete howto in the perfaq here: http://learn.perl.org/faq/perlfaq4.html#How-do-I-strip-blank-space-from-the-beginning-end-of-a-string-
For those that are using Text::CSV I found this thread and then noticed within the CSV module that you could strip it out via switch:
$csv = Text::CSV->new({allow_whitespace => 1});
The logic is backwards in that if you want to strip then you set to 1. Go figure. Hope this helps anyone.
One option is Text::Trim:
use Text::Trim;
print trim("  example  ");
Apply: s/^\s*//; s/\s+$//; to it. Or use  s/^\s+|\s+$//g if you want to be fancy.
I also use a positive lookahead to trim repeating spaces inside the text:
s/^\s+|\s(?=\s)|\s+$//g
No, but you can use the s/// substitution operator and the \s whitespace assertion to get the same result.
 
         
                                         
                                         
                                         
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