I am looking for a way to find a url in a string and convert it to a link.
The url may be anywhere in the string (beginning, midd开发者_开发百科le, or the end).
Regex is preferred but CPAN modules are welcome.
Most common solution is Regexp::Common (no pun intended). You need to use {-keep}
version as shown below to keep the match (in $1
, obviously)
use Regexp::Common qw /URI/;
while (<>) {
/$RE{URI}{HTTP}{-keep}/ and print "<A HREF="$1">My Link Name</A>";
}
As is hopefully obvious, the above example only finds 1 link per line. Fixing for more is left as exercise for the user.
Another option is Schwern's URI::Find. From POD example:
use CGI qw(escapeHTML);
use URI::Find;
my $finder = URI::Find->new(sub {
my($uri, $orig_uri) = @_;
return qq|<a href="$uri">$orig_uri</a>|;
});
$finder->find(\$text, \&escapeHTML);
print "<pre>$text</pre>";
use strict;
use warnings;
use 5.010;
use utf8;
use Regexp::Common qw /URI/;
my $string_with_url = <<'END_STRING';
This is an url to your question:
http://stackoverflow.com/questions/4587876/perl-convert-url-string-to-link
END_STRING
say $string_with_url;
$string_with_url =~ s/($RE{URI}{HTTP})/get_link()/eg;
say $string_with_url;
sub get_link {
return <<'END_LINK';
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END_LINK
}
You can use Regexp::Common to find the string and then do a substitution to make it into a links. In the absence of any thing else I have used the URL as the link text.
use Regexp::Common "URI";
my $string="Some text containing http://stackoverflow.com/questions/4587876/perl-convert-url-string-to-link in middle" ;
$string =~ s( ($RE{URI}{HTTP}) )
(<a href="$1">$1</a>)gx ;
print $string ;
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