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Sorting a std::vector<std::pair<std::string,bool>> by the string?

开发者 https://www.devze.com 2023-02-02 10:35 出处:网络
How can I sort this vector by comparing the p开发者_JS百科air.first which is an std::string? (without providing a static compare function, nor use boost).std::vector<std::pair<std::string, bool&

How can I sort this vector by comparing the p开发者_JS百科air.first which is an std::string? (without providing a static compare function, nor use boost).


std::vector<std::pair<std::string, bool> > v;
std::sort(v.begin(), v.end());

std::pair overloads operator< to sort first by the first element then by the second element. Thus, if you just sort the vector using the default sort ordering (operator<), you'll get your desired ordering.


I really like James' answer, but there's one other option you might want to consider - just funnel everything into a std::map:

std::map<std::string, bool> myMap(v.begin(), v.end());

Or, if you have duplicate strings, a std::multimap:

std::multimap<std::string, bool> myMultiMap(v.begin(), v.end());

This does have the added advantage that if you then need to add or remove new key/value pairs, you can do so in O(lg n), as opposed to O(n) for the sorted vector.

If you really must use a vector, then go with James' answer. However, if you have a vector of pairs, there's a good chance that you really want a std::map.


Answer to "duplicate question" of this: link: Sort a vector of pairs by first element then by second element of the pair in C++?

bool cmp(const pair<int,int>&x,const pair<int,int>y){
if(x.first==y.first){
   return(x.second<y.second);
}
return(x.first<y.first);
}

array of pairs before:
5 2
4 2
8 2
8 3
8 1
array of pairs after:
4 2
5 2
8 1
8 2
8 3


You can use a custom comparator to order on the pairs' .first only.

sort(begin, end,
     compose2(less<string>(),
              select1st<pair<string, bool> >(),
              select1st<pair<string, bool> >()));


You don't need to provide any compare function since by default since the sort() function will sort vector in ascending order of values. As each element is a pair, so one pair will be smaller than other one if the first value of one pair is smaller than that for other pair.

vector<pair<string,int>>v;
v = {{"xyz",1},{"pq",2}};   // Sample input
sort(v.begin(),v.end());    // Requires #include<algorithm> header
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