I've written a sed interpreter script:
#!/usr/bin/sed -E -f
s/ +/_/g
s/[.':]//g
s/&/and/g
However, when I run it:
$ echo "Bob Dylan" | shscrub.sed
sed: unkno开发者_如何学Gown option --
usage: sed [-aEnru] command [file ...]
sed [-aEnru] [-e command] [-f command_file] [file ...]
I need the -E option because I'm using the Extended Regular Expression syntax '+'.
Any ideas what I'm doing wrong?
Edit
A workaround:
#!/usr/bin/sed -f
s/ \{1,\}/_/g
s/[.':]//g
s/&/and/g
But, I'd still like to know how I can pass two parameters in the shebang (#!) line.
The error message was saying that the space character isn't an option. So I guess, you need to mash all the arguments together in the shebang:
#!/usr/bin/sed -Ef
s/ +/_/g
s/[.':]//g
s/&/and/g
Strange, because this works fine:
$ echo "Bob Dylan" | sed -E -f ~/bin/shscrub.sed
Bob_Dylan
The problem is the shebang #!
multiple CLI arguments which get treated as a single '-E -f' argument by the Linux kernel through binfmt_misc
: https://stackoverflow.com/a/1667855/895245
As mentioned in: How to use multiple arguments with a shebang (i.e. #!)? there seems to be no nice way to get around that except with a wrapper.
And since you mentioned POSIX, also note that there here is no mention of -E
in POSIX 7: http://pubs.opengroup.org/onlinepubs/9699919799/utilities/sed.html
Works with the default sed on OSX 10.6;
[~]> echo "Bob Dylan"|./test.sed
Bob_Dylan
Using plain sh
works too;
[~]> sh -c "echo \"Bob Dylan\" | ./test.sed"
Bob_Dylan
Update: Doesn't work with Gnu sed indeed, seems to be a compatibility problem.
With GNU sed
it works if you don't use the -f
parameter, note that you have to use -r
instead of -E
;
[~]> echo "Bob Dylan"|sed -r "s/ +/_/g;s/[.':]//g;s/&/and/g"
Bob_Dylan
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