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MVC Partial View not returning model on ajax postback

开发者 https://www.devze.com 2023-02-02 00:14 出处:网络
I have a view which has a partial view in it, which has a text box in it.The main view has a model of type person and the partial view a model of type person.other.When I do a ajax post back the other

I have a view which has a partial view in it, which has a text box in it. The main view has a model of type person and the partial view a model of type person.other. When I do a ajax post back the other model is empty, I expected it to pick up the textbox data. This is the code;

Classes

public class Person
    {
        public string PersonID { get; set; }
        public string Name { get; set; }
        public Other Other { get; set; }
    }

public class Other
    {
        public string OtherName { get; set; }
    }

Controller

[AcceptVerbs(HttpVerbs.Get)]
        public ActionResult Index()
        {
            Person person = new Person();
            person.Other = new Other();

            person.Other.OtherName = "avbc";    

            return View(person);
        }


        [AcceptVerbs(HttpVerbs.Post)]
        public ActionResult Test(Other other)
        {
            if (Request.IsAjaxRequest())
            {
                return PartialView("Test");
            }
            return null;
        }

View

@model PartialViewTest.Models.Person
<h2>Index</h2>

<div id="mydiv">
        @Html.Partial("Test", Model.Other)
</div>

PartialView

@model PartialViewTest.Models.Other


<h1>Test</h1>
@using (Html.BeginForm("Test", "Home", FormMethod.Post, new {  id开发者_如何学编程 = "testForm" })) { 

    @Html.TextBoxFor(m => m.OtherName)

    <input type="submit"/>

}

Jquery submit

$(document).ready(function () {

    $('#testForm').submit(function () {

        $.post($(this).attr("action"),
             $(this).serialize(),
            function (result) {
                $('#mydiv').html(result);
            });
        );
});


Make sure you cancel the default form submission by returning false from the submit callback. Also you seem to be missing a closing }:

$(document).ready(function () {
    $('#testForm').submit(function () {
        $.post($(this).attr("action"), $(this).serialize(), function (result) {
            $('#mydiv').html(result);
        });
        return false;
    });
});

Also you might need to modify your controller action like this because what is actually sent to the server is Other.OtherName=foo:

[AcceptVerbs(HttpVerbs.Post)]
public ActionResult Test([Bind(Prefix="Other")]Other other)
0

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