开发者_如何学GoPossible Duplicate:
How would I add a message that says “$user_id Deleted” or “$user_id not found?”
<?php
error_reporting(0);
$con=mysql_connect("localhost","root","");
if (!$con) {
die('could not connect:'.mysql_error());
}
mysql_select_db("final?orgdocs",$con);
$org_name = $_POST["org_name"];
$org_type = $_POST["org_type"];
$org_code = $_POST["org_code"];
$description = $_POST["description"];
$stmt = "INSERT INTO organization
VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')";
$result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' ");
echo '<TABLE BORDER = "1">';
$result1 = $result;
while ($row = mysql_fetch_array($result1)){
echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>';
echo '</TR>';
echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>';
echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>';
echo '</TR>';
}
echo '</TABLE>';
?>
$count = mysql_affected_rows();
echo "$count values inserted to table”;
Shortest answer : echo 'values inserted to table';
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