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Read a file with 2048 bytes

开发者 https://www.devze.com 2023-02-01 21:04 出处:网络
Guys i have a file which has only one line. The file has no encoding it is a simple text file with single line.

Guys i have a file which has only one line. The file has no encoding it is a simple text file with single line.

For every 2048 byte i开发者_C百科n a line , there is new record of 151 byte (totally 13*151 byte = 1945 records + 85 byte empty space). similarly for the next 2048 bytes.

What is the best file i/o to use? i am thinking of reading 2048 bytes from file and storing it in an array .

while (offset < fileLength &&(numRead=in.read(recordChunks, offset,alength)) >= 0) 
{ 
}

how can i get from the read statement only 2048 bytes at a time . i am getting IndexOutofBoundException.


Just use a FileInputStream, the various read methods will allow you to do what you need.


How about:

byte byte1 = dataArray[0];
byte byte2 = dataArray[1];


In my opinion, the easiest way to read data from a file is to use a BufferedReader :

try
{
    BufferedReader br = new BufferedReader(new FileReader("your_file"));

    //Read the first line
    String s = br.readLine();
}
catch(Exception e)
{
    e.printStackTrace();
}

Then just do what you want with the String you get !

Hope this helps.

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