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Java: Parsing for empty spaces using Pattern and Matcher

开发者 https://www.devze.com 2023-02-01 19:44 出处:网络
I have a form with an edit box for entering valid email-address. I dont want the user to enter spaces in the email id edit box. As soon a text is entered i call two funcs

I have a form with an edit box for entering valid email-address. I dont want the user to enter spaces in the email id edit box. As soon a text is entered i call two funcs

isEmailValid(String s) || isLoginValid(String s)
isEmailValid(String s){
    Pattern pattern = Pattern.compile("^[\\.\\w-]*(@[\\.\\w-]*)?$");
    Matcher matcher = pattern.matcher(string);
    return matcher.matches();
}

开发者_开发技巧isLoginValid(String s){
    Pattern pattern = Pattern.compile("^\\w+$");
    Matcher matcher = pattern.matcher(string);
    return matcher.matches();
}

This pattern works fine when the user enters the email-id for the first time. But as soon as the user deletes a char and enters a space, this logic breaks. I dont want user to enter spaces as email-id.

Can any help point out where i am going wrong?


I'm not 100% sure, but is it possible that it is matching the e-mails because it is matching your string because most everything is zero or more times? Followed by something that can happen zero or more times. Maybe try something like:

Pattern pattern = Pattern.compile("^[\\w]+[\\.\\w-]*(@[\\w-]+\\.[\\w-]+)?$");

I'm not sure if this will help. Also, You probably want both to have to be valid, but maybe not. It's worth considering if you wanted:

isEmailValid(String s) && isLoginValid(String s)

instead of:

isEmailValid(String s) || isLoginValid(String s)

but it's also possible (and potentially logical) that you meant what you wrote. Just a suggestion.


regexp are not universal matchers. the easiest way to solve your task is to make additional check for empty string:

 if (org.apache.commons.lang.StringUtils.isBlank(email)) {
    return false;
 }
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