I am trying to read customers.xml using javascript.
My professor has taught us to read xml using `ActiveXObjectand he has given us an assignment to create a sample login page which checks username and password by reading customers.xml.
I am trying to use DOMParser
so that it works with firefox.
But when I click on Login button I get this error.
Error: syntax error Source File: file:///C:/Users/Searock/Desktop/home/project/project/login.html Line: 1, Column: 1 Source Code: customers.xml
Here's my code.
login.js
var xmlDoc = 0;
function checkUser()
{
var user = document.login.txtLogin.value;
var pass = document.login.txtPass.value;
//xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
/*
xmlDoc = document.implementation.createDocument("","",null);
xmlDoc.async = "false";
xmlDoc.onreadystatechange = redirectUser;
xmlDoc.load("customers.xml");
*/
var parser = new DOMParser();
xmlDoc = parser.parseFromString("customers.xml", "text/xml");
alert(xmlDoc.documentElement.nodeName);
xmlDoc.async = "false";
xmlDoc.onreadystatechange = redirectUser;
}
function redirectUser()
{
alert('');
var user = document.login.txtLogin.value;
var pass = document.login.txtPass.value;
var log = 0;
if(xmlDoc.readyState == 4)
{
xmlObj = xmlDoc.documentElement;
var len = xmlObj.childNodes.length;
for(i = 0; i < len; i++)
{
var nodeElement = xmlObj.childNodes[i];
var userXml = nodeElement.childNodes[0].firstChild.nodeValue;
var passXml = nodeElement.childNodes[1].firstChild.nodeValue;
var idXML = nodeElement.attributes[0].value
if(userXml == user && passXml == pass)
{
log = 1;
document.cookie = escape(idXML);
document.login.submit();
}
}
}
if(log == 0)
{
var divErr = document.getElementById('Error');
divErr.innerHTML = "<b>Login Failed</b>";
}
}
customers.xml
<?xml version="1.0" encoding="UTF-8"?>
<customers>
<customer custid="CU101">
<user>jack</user>
<pwd>PW101</pwd>
<email>jack@rediff.com</email>
</customer>
<customer custid="CU102">
<user>jill</user>
<pwd>PW102</pwd>
<email>jill@rediff.com</email>
</customer>
<customer custid="CU103">
<user>john</user>
<pwd>PW103</pwd>
<email>john@rediff.com</email>
</customer>
<customer custid="CU104">
<user>jeff</user>
<pwd>PW104</pwd>
<email>jeff@rediff.com</email>
</customer>
</customers>
I get parsererror message on line alert(xmlDoc.documentElement.nodeName);
I don't know what's wrong with my code. Can some one point me in a right direction?
Edit :
Ok, I found a solution.
var xmlDoc = 0;
var xhttp = 0;
function checkUser()
{
var user = document.login.txtLogin.value;
var pass = document.login.txtPass.value;
var err = "";
if(user == "" || pass == "")
{
if(user == "")
{
alert("Enter user name");
}
if(pass == "")
{
alert("Enter Password");
}
return;
}
if (window.XMLHttpRequest)
{
xhttp=new XMLHttpRequ开发者_Go百科est();
}
else // IE 5/6
{
xhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xhttp.onreadystatechange = redirectUser;
xhttp.open("GET","customers.xml",true);
xhttp.send();
}
function redirectUser()
{
var log = 2;
var user = document.login.txtLogin.value;
var pass = document.login.txtPass.value;
if (xhttp.readyState == 4)
{
log = 0;
xmlDoc = xhttp.responseXML;
var xmlUsers = xmlDoc.getElementsByTagName('user');
var xmlPasswords = xmlDoc.getElementsByTagName('pwd');
var userLen = xmlDoc.getElementsByTagName('customer').length;
var xmlCustomers = xmlDoc.getElementsByTagName('customer');
for (var i = 0; i < userLen; i++)
{
var xmlUser = xmlUsers[i].childNodes[0].nodeValue;
var xmlPass = xmlPasswords[i].childNodes[0].nodeValue;
var xmlId = xmlCustomers.item(i).attributes[0].nodeValue;
if(xmlUser == user && xmlPass == pass)
{
log = 1;
document.cookie = xmlId;
document.login.submit();
break;
}
}
}
if(log == 0)
{
alert("Login failed");
}
}
Thanks.
parseFromString
is parsing the string "customer.xml" in your case, because the first argument needs to be a string containing the actual content of the XML document and not its name.
You can use something like this to get the xml file:
if (window.XMLHttpRequest)
{
xhttp=new XMLHttpRequest();
}
else // IE 5/6
{
xhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xhttp.open("GET","customer.xml",false);
xhttp.send();
xmlDoc=xhttp.responseXML;
Source
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