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form>table (ajax)>form

开发者 https://www.devze.com 2023-02-01 14:28 出处:网络
I want to do different action for each submit button. For example compare will go to \"compare.php\" and delete will go 开发者_开发百科to \"test.php\". I know i can\'t do form inside form but i can\'t

I want to do different action for each submit button. For example compare will go to "compare.php" and delete will go 开发者_开发百科to "test.php". I know i can't do form inside form but i can't separate to two forms because this is one table. I thought maybe to do

<?php if(isset($_POST["com"])){ javascript - link to compare.php}?>

but how can i send the _POST to this page? I also thought on send the ind as _GET but the user can select more then one (two deletes or two compares) of course if you have other solutions..

<html>
<head>
<script>
build ajax tbody...
for (i = 1; i <= numOfRows; i++)
{
oCell = oRow.insertCell(-1);
oCell.innerHTML = "<input type='checkbox' value='"+ ind +   "'name='com[]'>";
oCell = oRow.insertCell(-1);
oCell.innerHTML = "<input type='checkbox' value='"+ ind +   "'name='del[]' ;>";
.....
</script>
<body>
    <form method="post" action="test.php">
        <table>
            <thead>
             <tr>
                 <th><input type="submit" value="Compare" /></th>
                 <th><input type="submit" value="Delete" /></th>
             </tr>
            </thead>
            <tbody></tdbody>
         </table>
     </form>
</body>
</html>

Thank you!


You can simply have:

<input type="submit" value="Compare" onclick="this.form.action = 'someotherpage.php';" />

This will change the form action upon clicking the submit button.

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