I have a Java application that I CAN'T EDIT that starts a java.lang.Thread
that has this run()
method:
public void run(){
while(true){
System.out.println("Something");
}
}
At a certain point in time I want to stop it. If I use Thread.interrupt()
it doesn't work.
If I use Thread.stop()
it works, but t开发者_开发百科his method is deprecated (so its use is discouraged as it may be removed from JVM in new releases).
How to stop such uninterruptible threads in Java?
The java debugger will allow you to kill a thread by injecting an exception into it.
Start your Java process and have it listen on some port:
java -Xdebug -Xrunjdwp:transport=dt_socket,server=y,suspend=n,address=4444 <Your Program>
and connect the debugger with something like:
jdb -attach 127.0.0.1:4444
and issue the following command:
threads
to get a list of the running threads, and use the kill command to kill a running thread.
kill 0xe2e new java.lang.IllegalArgumentException("er");
Under this link: http://download.oracle.com/javase/6/docs/technotes/guides/concurrency/threadPrimitiveDeprecation.html:
What if a thread doesn't respond to Thread.interrupt?
In some cases, you can use application specific tricks. For example, if a thread is waiting on a known socket, you can close the socket to cause the thread to return immediately. Unfortunately, there really isn't any technique that works in general. It should be noted that in all situations where a waiting thread doesn't respond to Thread.interrupt, it wouldn't respond to Thread.stop either. Such cases include deliberate denial-of-service attacks, and I/O operations for which thread.stop and thread.interrupt do not work properly.
You can't reliably interrupt a thread without cooperation from that thread.
As an ugly hack (not for practical use!), you can substitute System.out
and make println
throw an exception when interruption condition is met and the thread in question is a current thread (i.e. use it as a hook to provide some cooperation in context of the target thread).
EDIT: Even more elegant option - you can make println
interruptable by throwing an exception when Thread.interrupted()
is true
, so that the thread can be interrupted by calling thread.interrupt()
.
Semantic of this method would be very close to the ordinary interruptable methods (i.e. methods that throw InterruptedException
), although you can't use InterruptedException
since it's a checked exception and need to use unchecked RuntimeException
instead:
System.setOut(new PrintStream(System.out) {
public void println(String s) {
if (Thread.interrupted()) throw new RuntimeException();
super.println(s);
}
});
You can implement the interrupt method using a check variable.
First of all use a volatile check variable as:
volatile boolean tostop = false; // Keep the initial value to be false
Next define your thread to be dependent to this variable.
Thread thread1 = new Thread(){
public void run() {
while(!tostop) {
-- Write your code here --
}
}
}
Next define the function in which to use the thread:
public void ....{
//Interrupt code
tostop = true;
thread1.sleep(300); // Give the thread sometime for cleanup
//Use System.exit(0), if the thread is in main function.
}
Hope this helps.
I am not aware of any deprecated method which has been removed from the JRE ever. stop() has been deprecated a very long time, possibly more than 10 years. Its a bad idea to use it, but it may be your best option.
Ok, I've found the solution and it's really really simple, just sleep the thread and then interrupt it!
final Thread t = getTheThreadToClose();
//Final is important because only in this way you can pass it to the following new Thread
if (t != null && t.isAlive() && !t.isInterrupted()){
try{
new Thread(){
public void run(){
try{
t.sleep(3000);//SLEEP INSIDE THE NEW THREAD
}
catch(InterruptedException ex){}
}
}.start();
t.interrupt();//INTERRUPT OUTSIDE THE NEW STARTED THREAD
}
catch(Exception e){}
}
It works in all cases!
I wanna thank you all for your really useful help, especially venomrld and Toby that gave me inspiration for the solution with their words ;-), and this wonderfoul site that let me ALWAYS solve all my programming problems.
Thank you all again and Happy New Year!
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