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Core Data: Count across relationships

开发者 https://www.devze.com 2023-02-01 01:43 出处:网络
I have three models: +----------++--------------++------+ Occasion | <--->> | GiftOccasion | <--->>开发者_开发技巧 | Gift |

I have three models:

+----------+        +--------------+        +------+
| Occasion | <--->> | GiftOccasion | <--->>开发者_开发技巧 | Gift |
+----------+        +--------------+        +------+

I've like to get the name of the occasion, and a count of all the gifts that meet certain criteria. Currently I'm getting the distinct list of occasions sorted by year and name:

NSFetchRequest *request = [[NSFetchRequest alloc] init];
[request retain];
NSEntityDescription *entity = [NSEntityDescription entityForName:@"Occasion" inManagedObjectContext:[self managedObjectContext]];
[request setEntity:entity];
[request setResultType:NSDictionaryResultType];

[request setPropertiesToFetch:[NSArray arrayWithObjects:@"name", @"year", nil]];    
[request setReturnsDistinctResults:YES];

NSSortDescriptor *yearDescriptor = [[[NSSortDescriptor alloc] initWithKey:@"year" ascending:NO selector: @selector(caseInsensitiveCompare:)] autorelease];
NSSortDescriptor *nameDescriptor = [[[NSSortDescriptor alloc] initWithKey:@"name" ascending:YES selector: @selector(caseInsensitiveCompare:)] autorelease];
NSArray *descriptors = [NSArray arrayWithObjects:yearDescriptor, nameDescriptor, nil];
[request setSortDescriptors:descriptors];

NSError *error = nil;
NSArray *results = [[self managedObjectContext] executeFetchRequest:request error:&error];  

... but I'm totally stumped as to how to get the count of Gift. Is there a straightforward way, or do I need to traverse each GiftOccasion and related Gifts and add it all together?

ETA: Note that I'm generating distinct results, here, not getting the model directly. I assume I'd have to run another request to get this information, but if it's possible not to, that would be better.

Thanks!


Get number of objects in a Core Data relationship


This isn't a good answer, and I'm not going to select it as the "right" answer, but what I ended up doing was a ridiculous set of nested NSEnumerators that go through each relationship and eventually do a count += 1;, something like this:

    NSUInteger giftCount = 0;


    NSEnumerator *oEnum = [resultsList objectEnumerator];
    Occasion *occasion = nil;
    while (occasion = [oEnum nextObject]) {

        NSEnumerator *goEnum = [occasion.giftOccasions objectEnumerator];
        GiftOccasion *go;

        while (go = [goEnum nextObject]) {
            if (go.gifts) {

                NSEnumerator *giftEnum = [go.gifts objectEnumerator];
                Gift *gift = nil;
                while (gift = [giftEnum nextObject]) {
                    NSLog(@"Gift: %@ %@", gift.name, gift.purchased);
                    if ([gift.purchased boolValue] == NO) {
                        giftCount += 1;
                    }
                }
            }
        }
    }

Embarrassing, but it works. :-)

If there is a better, more efficient way to do this, I'd love to hear it. It's one of the things I dislike about Core Data as an ORM vs., say, ActiveRecord.

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