Checking if string contains "HTTP://"

I am wondering why this code is not working:

// check to see if string contains "HTTP://" in front

if(strpos($URL, "http://"开发者_JAVA技巧)) $URL = $URL;
else $URL = "http://$URL";

If it does find that the string doesn't contain "HTTP://" the final string is "HTTP://HTTP://foo.foo" if it contiains "http://" in front.

---

Because it's returning 0 for that string, which evaluates to false. Strings are zero-indexed and as such if http:// is found at the beginning of the string, the position is 0, not 1.

You need to compare it for strict inequality to boolean false using !==:

if(strpos($URL, "http://") !== false)

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@BoltClock's method will work.

Alternatively, if your string is a URL you can use parse_url(), which will return the URL components in an associative array, like so:

print_r(parse_url("http://www.google.com.au/"));


Array
(
    [scheme] => http
    [host] => www.google.com.au
    [path] => /
)

The scheme is what you're after. You can use parse_url() in conjunction with in_array to determine if http exists within the URL string.

$strUrl       = "http://www.google.com?query_string=10#fragment";
$arrParsedUrl = parse_url($strUrl);
if (!empty($arrParsedUrl['scheme']))
{
    // Contains http:// schema
    if ($arrParsedUrl['scheme'] === "http")
    {

    }
    // Contains https:// schema
    else if ($arrParsedUrl['scheme'] === "https")
    {

    }
}
// Don't contains http:// or https://
else
{

}

Edit:

You can use $url["scheme"]=="http" as @mario suggested instead of in_array(), this would be a better way of doing it :D

---

if(preg_match("@^http://@i",$String))
    $String = preg_replace("@(http://)+@i",'http://',$String);
else
    $String = 'http://'.$String;

---

You need to remember about https://. Try this:

private function http_check($url) {
    $return = $url;
    if ((!(substr($url, 0, 7) == 'http://')) && (!(substr($url, 0, 8) == 'https://'))) {
        $return = 'http://' . $url;
    }
    return $return;
} 

---

you have checking if string contains “HTTP://” OR Not

Below code is perfectly working.

<?php 
$URL = 'http://google.com';
$weblink =   $URL; 
    if(strpos($weblink, "http://") !== false){ }
    else { $weblink = "http://".$weblink; }
 ?>
  <a class="weblink" <?php if($weblink != 'http://'){ ?> href="<?php echo $weblink; ?>"<?php } ?> target="_blank">Buy Now</a>

Enjoy guys...

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You can use substr_compare() [PHP Docs].

Be careful about what the function returns. If the strings match, it returns 0. For other return values you can check the PHP docs. There is also a parameter to check case-sensitive strings. If you specify it TRUE then it will check for upper-case letters.

So you can simply write as follows in your problem:

if((substr_compare($URL,"http://",0,7)) === 0) $URL = $URL;
else $URL = "http://$URL";

---

One line solution:

$sURL = 'http://'.str_ireplace('http://','',$sURL);