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Undefined test not working in javascript

开发者 https://www.devze.com 2023-01-31 21:42 出处:网络
I\'m getting the error \'foo\' is undefined. in my script when i test my function with an undefi开发者_运维问答ned parameter. As far as I understand, This shouldn\'t be happening.

I'm getting the error 'foo' is undefined. in my script when i test my function with an undefi开发者_运维问答ned parameter. As far as I understand, This shouldn't be happening.

My calling code:

//var foo
var test = peachUI().stringIsNullOrEmpty(foo) ;

My function (part of a larger framework).

    stringIsNullOrEmpty: function (testString) {
        /// <summary>
        ///     Checks to see if a given string is null or empty.
        /// </summary>
        /// <param name="testString" type="String">
        ///     The string check against.
        /// </param>
        /// <returns type="Boolean" />

        var $empty = true;

        if (typeof testString !== "undefined") {
            if (testString && typeof testString === "string") {

                if (testString.length > 0) {
                    $empty = false;
                }

            }
        }
        return $empty;
    }

Any ideas?

Please note. I've had a good read of other similar questions before posting this one.


You can't pass a variable that doesn't exist (undefined, not null...which does exist) into a function, it's trying to get the value of foo to pass it when you call

var test = peachUI().stringIsNullOrEmpty(foo);

...and it isn't there, so you're getting the error on just that line, just as you would with a simpler case:

alert(foo);

Now if you tried to call it as a property of something, then it'd be valid, for example:

alert(window.foo);

Then undefined gets passed in, because it's an undefined property on a known/present object.


I get the error too, but it is is not related to your code, it is because you pass a variable that does not exist to a function. This works:

var foo = undefined;
var test = peachUI().stringIsNullOrEmpty(foo) ;

Btw. the error already tells you that the problem is not in your function, otherwise it be 'testString' is undefined.

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