Windows Form UserControl design time properties

I am struggling with a UserControl. I have a UserControl that represent a Pager and it has a Presenter object property exposed in this way:

[Browsable(false)]
[DesignSerializationAttribute(DesignSerializationAttribute.Hidden)]    
public object Presenter { get; set; }

The code itself works as I can drag and drop a control into a Windows From without having Visual Studio initializing this property. Now, because in the Load event of this control I call a method of the Presenter that at run-time is null ... I have introduced this additional code:

public override void OnLoad(...)
{
   if (this.DesignMode)
   {
      base.OnLoad(e);
      return;
   }
   presenter.OnViewReady();
}

Now, every time I open a Window that contains this UserControl, Visual Studio modifies the Windows designer code. So, as soon as I open it, VS ask me if I want to save it ... and of course, if I add a control to the Window, it doesn't keep the changes ... As soon as I remove the UserControl Pager the problem disappears ... How should I tackle that in the proper way? I just don't want that the presenter property is initialized at design time as it is injecte开发者_如何学JAVAd at runtime ...

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You're probably getting an exception when VS tries to generate the designer code.

Attach a second copy of VS to the designer, turn on Break On Exceptions, and see what's going on.

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So the exception is thrown by the Designer of the Windows form that contains the UserControl:

Instances of this error (1)

1. Infrastructure.BaseModule.MYWindow.Designer.cs Line:108 Column:1 Hide Call Stack

at System.ComponentModel.Design.Serialization.CodeDomSerializerBase.Error(IDesignerSerializationManager manager, String exceptionText, String helpLink) at System.ComponentModel.Design.Serialization.CodeDomSerializerBase.DeserializeExpression(IDesignerSerializationManager manager, String name, CodeExpression expression) at System.ComponentModel.Design.Serialization.CodeDomSerializerBase.DeserializeExpression(IDesignerSerializationManager manager, String name, CodeExpression expression) at System.ComponentModel.Design.Serialization.CodeDomSerializerBase.DeserializeStatement(IDesignerSerializationManager manager, CodeStatement statement)