PHP: Wrapping built-in function (filter_input) and optional parameters

So, I know that with PHP you can define optional parameters (StackOverflow Questions).

What I'm trying to do is the following:

function myFunc($a, $b, $c, $type, $variable_name, $filter, $options)
{
   $value = filter_input($type, $variable_name, $filter, $options);

   //Do something with $a, $b, $c, and $value
}

Since I am passing in parameters that pertain to the built in function of filter_input I know that $filter and $options 开发者_如何学JAVAare optional parameters, and to make them optional I would simply assign them a default value. But, I'm not sure what that default value should be. My guess is that $filter should default to FILTER_DEFAULT, which makes sense, but I can not find any information as to what $options should default to.

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Default both $filter and $options to NULL. They are optional for filter_input() as well, so why assign them a value when filter_input() will do it for you? If PHP were ever to update the defaults for the function then you'd still be current, too.

Your function would look like this:

function myFunc($a, $b, $c, $type, $variable_name, $filter=NULL, $options=NULL)
{...

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As the options argument for the filter_input function is er.. optional and can be either an array or a bitmask, so I suspect using...

function myFunc($a, $b, $c, $type, $variable_name, $filter, $options=null) {
    ...

..would be ideal, unless there's an application specific reason for doing otherwise.

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The documentation on the filter_input method suggests that the expected value is an integer so it would probably be 0.