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Best way to perform XSL transformation in Ruby (XSLT 2.0)

开发者 https://www.devze.com 2023-01-31 09:27 出处:网络
What would be the best and most efficient way to to perform XSL transformation in Ruby? I have tried Nokogiri, but no matter what I tried it always results in:

What would be the best and most efficient way to to perform XSL transformation in Ruby? I have tried Nokogiri, but no matter what I tried it always results in:

compilation error: element stylesheet

The stylesheet works perfectly in my XML editor.

I'm using Ruby 1.9.3 on Linux.


After poking around, I found out that Nokogiri does not support XSLT 2.0:

Nokogiri uses libxml2, which only supports XPath 1.0/XSLT1.0

My stylesheet was written using XSLT 2.0 syntax. I updated the title of this question to reflect this. I wish Nokogiri responded to it in a more meaningful way.

Why do you want to perform an XSL transformation? Just curious.

I'm working on a website that submits XML feeds to other sites. Every feed has a different format, but the source of data for the feed is the same. So, instead of writing custom code for every feed I decided to use XSL stylesheets, served from a database. This wa开发者_开发技巧y I can create new feeds just by uploading a new stylesheet.


It is possible to use XSLT 2.0 in JRuby via the saxon-xslt gem. I don't think it's possible to do it via other Ruby implementations. Certainly MRI ruby would depend on libxml which hasn't implemented XPath 2.0 yet. See this thread for more information.

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