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Output in makefile at top-level

开发者 https://www.devze.com 2023-01-31 09:23 出处:网络
I am setting a variable in a makefile like this: SOMEVAR = foo This makefile later includes some other makefile in which the actual building of programs takes place:

I am setting a variable in a makefile like this:

SOMEVAR = foo

This makefile later includes some other makefile in which the actual building of programs takes place:

include generic/Makefile.common

So no build targets are defined in the first makefile, it's only setting up variables which are then used by the common generic makefile to do the actual package building.

Now I know that I should be careful when using foo, so to remind myself of this, I want to print a warning message whenever this makefile is used to setup th开发者_如何学Pythone make process. The problem is that I cannot just insert an echo command after the variable definition, because we are not yet building something there.

Is there a solution (more elegant than adding a fake target where the message is printed which would destroy the separation of setting variables and building)?


SOMEVAR = foo
$(warning be careful with foo)


According with official documentation there is three ways to do a top-level output in a makefile

  1. $(error text)
  2. $(warning text)
  3. $(info text)

Just in case you want do that in another way.

I hope helps.

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