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Storing Open Hours/Holidays

开发者 https://www.devze.com 2023-01-31 08:22 出处:网络
What kind of SQL schema would you suggest for storing hours and holidays, and what kind of query to check if a restaurant is open? Right now I have this:

What kind of SQL schema would you suggest for storing hours and holidays, and what kind of query to check if a restaurant is open? Right now I have this:

CREATE TABLE hours (
    "restaurant" integer NOT NULL REFERENCES restaurants ON DELETE CASCADE,
    "dow" integer NOT NULL,
    "open" time NOT NULL,
    "close" time NOT NULL
);
CREATE FUNCTION is_open(r integer) RETURNS boolean AS $$
    DECLARE
        h record;
        t time;
    BEGIN
        SELECT open, close INTO h
        FROM hours WHERE restaurant = r AND dow = EXTRACT(dow FROM now());
        IF NOT FOUND THEN
            RETURN false;
        END IF;
        t := current_time;
        IF h.close <= h.open THEN
            RETURN (t < h.close OR t > h.open);
        ELSE
            RETURN (t > h.open AND t < h.close); 
        END IF;
    END;
$$ LANGUAGE plpgsql;

But that doesn't really work, because, for instance, a restaurant might be open until 2:00 am, at which point I would need to check for the previous dow.

To make matters a little more complicated, I have to deal with holidays:

CREATE TABLE holidays (
    "restaurant" integer NOT NULL REFERENCES restauraunts ON DELETE CASCADE,
    "day" date NOT NULL
);

Which has the same problem - if a restaurant is open from 15:30 to 2:00, that means they are also closed for the block from midnight to two.

I haven't been able to wrap m开发者_如何学JAVAy head around finding a clean, elegant solution for this (several messy ones have come and gone). I need to go take a walk and come back to it - in the mean time, I figured I would let you guys take a crack at it.


Seems kind of wrong to answer my own question, but I've found something that seems to work, as messy as it is:

CREATE FUNCTION is_open(r integer) RETURNS boolean AS $$
    DECLARE
        t time;
        yesterday date;
        dow_today integer;
        dow_yesterday integer;
    BEGIN
        t := current_time;
        yesterday := current_date - 1;
        dow_today := EXTRACT(dow FROM current_date);
        dow_yesterday := EXTRACT(dow FROM yesterday);
        PERFORM * FROM hours
        WHERE restaurant = r AND ((
            dow = dow_today
            AND NOT EXISTS(
                SELECT * FROM holidays 
                    WHERE restaurant = r AND day = current_date
            ) AND (
                (open < close AND t > open AND t < close)
                OR (open >= close AND t > open)
            )
        ) OR (
            open >= close AND dow = dow_yesterday
            AND NOT EXISTS(
                SELECT * FROM holidays 
                WHERE restaurant = r AND day = yesterday
            ) AND t < close
        ));   
        RETURN FOUND;
    END;
$$ LANGUAGE plpgsql;


To sum up the comments:

1 - Use the general query structure from this question.

2 - Add a bit flag to your table for ClosePastMidnight or OpenPastMidnight (whichever works best for your way of thinking) that indicates close is on next calendar day, and adjust your logic accordingly.


Your table design has missing information that becomes apparent when you try to disambiguate what close and opening means. Such as 12 to 2. Does that mean 2 hours or 14? Without making assumptions there is no way to solve it.

Use intervals:

For example if your restaurant is from 1:30PM to 1:30AM this could check if now() is inbetween:

test=# select  
  now() > (now()::date || ' 13:30')::timestamp 
  and now() < (now()::date || ' 13:30')::timestamp + interval '12 hours';

 ?column?
----------
 t
(1 row)

That way only the starting dow is important and you should not have any wraparound problems.

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