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Checking a number with regular expressions in Java

开发者 https://www.devze.com 2022-12-11 09:52 出处:网络
I have a numb开发者_开发技巧er \"8756342536\". I want to check whether the number starts with \"8\", contains 10 digits all of it is numeric, using regular expression.

I have a numb开发者_开发技巧er "8756342536". I want to check whether the number starts with "8", contains 10 digits all of it is numeric, using regular expression.

What pattern would I need for this scenario in Java? Thanks in advance.


Use String's matches(...) method:

boolean b = "8756342536".matches("8\\d{9}");


Use this expression:

^8\d{9}$

meaning an 8 followed by exactly 9 digits. So for example:

String number = ...
if (number.matches("^8\\d{9}$")) {
  // it's a number
}


Given the number is in String form:

String number = "8756342536";
boolean match = number.matches ("^[8][0-9]{9}$");
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