How come when I run this main.cpp
:
#include <iostream>
#include <typeinfo>
using namespace std;
struct Blah {};
int main() {
cout << typeid(Blah).name() << endl;
return 0;
}
By compiling it with GCC version 4.4.4:
g++ ma开发者_如何学运维in.cpp
I get this:
4Blah
On Visual C++ 2008, I would get:
struct Blah
Is there a way to make it just print Blah
or struct Blah
?
The return of name
is implementation defined : an implementation is not even required to return different strings for different types.
What you get from g++ is a decorated name, that you can "demangle" using the c++filt
command or __cxa_demangle
.
The string returned is implementation defined.
What gcc is doing is returning the mangled name.
You can convert the mangled name into plain text with c++filt
> a.out | c++filt
Is there a way to make it just print
Blah
orstruct Blah
?
No. The result of std::typeinfo::name()
is unspecified. It might even return the same string for all types (or, indeed, empty strings for all types) and the implementation would still be standard-conforming. You must not rely on its result. Really, the only thing I found it useful for was debugging.
Tell us what what you need it for. Often traits is what you use instead.
As others have said, the result here is implementation-defined, meaning that the implementation (i.e., the compiler toolchain) is free to define it how it wants, so long as it documents that somewhere.
From the C++ standard, section 18.5.1/1 [lib.type.info]:
The class
type_info
describes type information generated by the implementation. Objects of this class effectively store a pointer to a name for the type, and an encoded value suitable for comparing two types for equality or collating order. The names, encoding rule, and collating sequence for types are all unspecified and may differ between programs.
in 4Blah, 4 is the number of letters in your class name. For example if your class name is myEmptyClass then it would print 12myEmptyClass.
typeid().name()
is implementation dependent. It may even return empty string for every type. That would not be very useful implementation, but it would be valid.
Use ./a.out | c++filt --types for GCC.
For more information follow the links below.
https://sourceware.org/binutils/docs/binutils/c_002b_002bfilt.html#:~:text=The%20c%2B%2Bfilt%201,that%20they%20can%20be%20read.&text=If%20the%20name%20decodes%20into,the%20original%20word%20is%20output.
精彩评论