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Clojure's # lambda marco is not always the same as (fn)?

开发者 https://www.devze.com 2023-01-30 16:29 出处:网络
user> (map (fn [k] [k]) [1 2 3]) ([1] [2] [3]) user> (map #([%1]) [1 2 3]) .... Error.. Why i开发者_如何学运维s the second example an error?The #(<expr>) reader macro wraps the <expr&
user> (map (fn [k] [k]) [1 2 3])
([1] [2] [3])
user> (map #([%1]) [1 2 3])
.... Error..

Why i开发者_如何学运维s the second example an error?


The #(<expr>) reader macro wraps the <expr> in an extra set of parenthesis, so #([%1]) expands to something equivalent to (fn [%1] ([%1])) and not (fn [%1] [%1]). So you are right. They are not entirely equivalent.

You can try the following in the REPL which will reveal the exact expansion:

user=> '#([%1])                   
(fn* [p1__862#] ([p1__862#]))
user=> '#(inc %1) 
(fn* [p1__865#] (inc p1__865#))
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