I’m reading some C code that can be found at https://home.hccnet.nl/h.g.muller/umax4_8.c.
There, in main()
, it has the following:
N=-1;W(++N<121)
printf("开发者_高级运维%c",N&8&&(N+=7)?10:".?+nkbrq?*?NKBRQ"[b[N]&15]);
I don’t understand what this printf()
call is doing, but somehow it outputs a chess board to the terminal.
Any idea?
Basically, this:
for (n = 0; n < 121; ++n) {
if (n & 8) {
n += 7;
putchar('\n');
} else {
putchar(".?+nkbrq?*?NKBRQ"[b[n] & 15]);
}
}
What that does is, after every 8 board items, print a newline; otherwise, print out the board item indicated by b[n]
.
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