Bash: how do i choose rows from a file that have particular value in the column

I have a huge file that I need to analyze. What I want to do is separate those rows that have certain values in a certain column. So, its like choosing only those data that belong to a certain category. How can this be accomplished with a simple bash commnand or script.

For example, I want to 开发者_JAVA百科separate only those rows which have values 1, 2 3 or 4 in the 8th column. The file is space delimited.

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You can use awk as:

awk '$8 == 1 || $8 == 2 || $8 == 3 || $8 == 4' file

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Yet another AWK answer:

awk '$8 ~ /1|2|3|4/' inputfile

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Use awk:

awk '$8 >= 1 && $8 <= 4' your_file.txt

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Yet another awk answer.

awk '$8 ~ /[1-4]/' file

But, just for some variety, a bash answer

while read line ; do
    fields=($line)
    [[ ${fields[7]} =~ [1-4] ]] && echo $line
done < file