From server I get data as such:
"07.00 PROGRAM DESCRIPTION"
"07.20 PROGRAM DESCRIPTION 2"
I want to split them into a 2 indexed array such as: ["07.00", "PROGRAM DESC开发者_运维百科RIPTION 2"]
. Regular split( " " ) would not work me as the description part contains severaral " " spaces.
I will be grateful for any suggestion.
Regards
You could use:
var parts = str.split(' '),
time = parts.shift(),
description = parts.join(' ');
or, to get your array:
var parts = str.split(' ');
parts[1] = parts.slice(1).join(' ');
;)
You need somekind of a pattern, which is reliable. If it's always the case that you need to split just between the first whitespace character to you can do:
var blub = "07.00 PROGRAM DESCRIPTION",
pos = blub.indexOf(" "),
arr = [];
arr[0] = blub.slice(0, pos);
arr[1] = blub.slice(pos + 1);
or you might just want to use regular expression. Since I don't pretend to be a genius on that field here is my little suggestion:
var blub = "07.00 PROGRAM DESCRIPTION",
arr = /(\d+\.\d+)\s(.*)/.exec(blub);
var pattern = /([0-9]{2}\.[0-9]{2})\s(.+)/;
var data = "07.00 PROGRAM DESCRIPTION";
var parsed = pattern.exec(data);
console.log(parsed); // (Array) ["07.00 PROGRAM DESCRIPTION", "07.00", "PROGRAM DESCRIPTION"]
this is flexible and easier to adapt in case the format changes (just change the pattern and use that var anywhere else in your code)
The substring method:
var time = row.substring(0,4);
var description = row.substring(5);
Or, with the split method:
row = row.split(" ",1);
The second parameter is the maximum number of splits... so it'll only split at the first space. Edit: this won't work. Use the first method instead.
精彩评论