There's plenty examples available on how to sort an javascript array based on it's numeric values. What 开发者_开发百科would however be appropriate way to fetch all elements from myArray
with the property prop1
with it's according value value1
?
Here's my array:
var myArray = [
{
"id":"2",
"name":"My name",
"properties":{"prop1":"value1"}
}];
Thanks
You can just access it by dot or bracket notation and push the matching members to your new/filtered array, for example:
var newArray = [];
for(var i=0, l = myArray.length; i<l; i++) {
if(myArray[i].properties.prop1 == "value1") newArray.push(myArray[i]);
}
Your question is a bit ambiguous though, if you're trying to get the {"prop1":"value1"}
object, not the parent, then just change newArray.push(myArray[i])
to newArray.push(myArray[i].properties)
.
Provide a compare function to sort by arbitrary properties:
function compareMyObjects(a, b) {
var valA = a.properties.prop1.value1;
var valB = b.properties.prop1.value1;
if(valA > valB) return 1;
if(valA < valB) return -1;
return 0;
}
myArray.sort(compareMyObjects);
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/sort
Go through each element in your array. For each element, check each property to see if it matches the one you're looking for.
function filterArray(array, property, value) {
var newArray = [];
for (var i = 0; i < array.length; i++) {
for (var j in array[i].properties) {
if (j === property && array[i].properties.hasOwnProperty(j)) {
if (array[i].properties[j] == value) {
newArray.push(array[i]);
}
}
}
}
}
var newarray=myarray.filter(function(itm){
return itm.properties.prop1==='value1';
});
Filter, like the array methods indexOf and map, may be worth providing for browsers that don't have it- this version is from Mozilla Developer Site-
if(!Array.prototype.filter){
Array.prototype.filter= function(fun, scope){
var L= this.length, A= [], i= 0, val;
if(typeof fun== 'function'){
while(i< L){
if(i in this){
val= this[i];
if(fun.call(scope, val, i, this)){
A[A.length]= val;
}
}
++i;
}
}
return A;
}
}
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