I want to write a query to select from a table开发者_运维问答 all rows with the word "piggy" in a column called Description.
SELECT * FROM table WHERE ...?
Thank you!
In MySQL, %
is a wild-card. You don't use wild-cards with the =
operator but with the LIKE
operator.
SELECT * FROM table WHERE `Description` LIKE "%piggy%"
http://dev.mysql.com/doc/refman/5.0/en/string-comparison-functions.html
select * from table where description like '%piggy%'
will select and return all rows where the word piggy is part of the value of the column. If you want to count how many rows then:
select count(*) from table where description like '%piggy%'
select * from table where description like '%piggy%'
As mentioned several times you need a LIKE
query for this. I would only warn that this is going to be terribly slow in case of a InnoDB
table as it doesn't support fulltext scans. If you want better performance with a LIKE
, then you should use MyISAM
.
Anyway, if you want to implement a search engine, better look for existing API's. I don't know what programming language you're using, but if it was Java, I'd recommend Apache Lucene.
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