Datetime - 10 Hours

Consider:

now = datetime.datetime.now()
now
datetime.datetime(2009, 11, 6, 16, 6, 4开发者_JS百科2, 812098)

How would I create a new datetime object (past) and minus n values from the hours?

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Use timedelta in the datetime module:

import datetime
now = datetime.datetime.now()
past = now - datetime.timedelta(hours=10)

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Use a timedelta object.

>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2009, 11, 6, 16, 35, 50, 593000)
>>> ten_hours = datetime.timedelta(hours=10)
>>> now + ten_hours
datetime.datetime(2009, 11, 7, 2, 35, 50, 593000)
>>> now - ten_hours
datetime.datetime(2009, 11, 6, 6, 35, 50, 593000)

---

Use a timedelta object.

from datetime import datetime
back = datetime.now() - timedelta(hours=10)