This program supposed to find command line arguments entered on Unix which ends with “.exe”. For some reason it doesn't work. Here is the code:
int main( int argc, char* argv[] )
{
for ( int i = 1; i < argc; i++)
if( findExe( argv[i] ) )
cout << argv[i] << endl;
return 0;
}
bool findExe( char* argument )
{
if ( strlen( argument ) >= 4 )
{
string testExe = ".exe";
string initialWord=argument; //converts c-string to string
string temp( initialWord,( initialWord.size() - 4 ),4 );//cr开发者_如何学运维eates temp with last four characters from initialWord
if ( !temp.compare(testExe) )
return true;
}
else
return false;
}
Remove the else
, I think (although I haven't compiled the code to check). In the case where the length is at least 4, but the string comparison returns non-zero, you reach the end of the function without returning. Your compiler should have warned you: turn on more warnings.
Your findExe function is has a branch that doesn't return a result....like Steve said, compiler should've warned you.
How about this?
bool findExe( char* argument )
{
int n = strlen(argument);
if (n < 4) return false;
char* ext = argument[n-4];
if (strcmp(ext, ".exe") == 0) return true;
return false;
}
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