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ERRORLEVEL inside IF

开发者 https://www.devze.com 2023-01-29 06:41 出处:网络
Just stumbled into a weird thing with %ERRORLEVEL% and wanted to see if anyone knows why and if there\'s a way to fix it. Essentially, it seems as if commands executed inside if statements don\'t set

Just stumbled into a weird thing with %ERRORLEVEL% and wanted to see if anyone knows why and if there's a way to fix it. Essentially, it seems as if commands executed inside if statements don't set the %ERRORLEVEL% variable开发者_JAVA百科. The ERRORLEVEL (as in IF ERRORLEVEL 1, which is different from IF %ERRORLEVEL% EQU 1 ) check seems to still work fine though, so I can probably work around it, but it would still be nice to be able to print the error level. For debugging or whatever.

@echo off
Set TESTVAR=1

tasklist | find /I "IsntRunning.exe" > NUL
echo OUTSIDE_IF %ERRORLEVEL%

ThisWillSetErrorLevelTo9009ieNotRecognizedCommand

tasklist | find /I "IsntRunning.exe" > NUL
echo OUTSIDE_IF %ERRORLEVEL%

ThisWillSetErrorLevelTo9009ieNotRecognizedCommand

IF %TESTVAR% EQU 1 (
    Set ERRORLEVEL=
    tasklist | find /I "IsntRunning.exe" > NUL
    echo INSIDE_IF  ERRORLEVEL %ERRORLEVEL%

    IF ERRORLEVEL 1 (
        echo INSIDE_IF2  ERRORLEVEL GREQ 1 %ERRORLEVEL%
    )
    IF ERRORLEVEL 2 (
        echo INSIDE_IF2  ERRORLEVEL GREQ 2 %ERRORLEVEL%
    )
    IF ERRORLEVEL 3 (
        echo INSIDE_IF2  ERRORLEVEL GREQ 3 %ERRORLEVEL%
    )
)

tasklist | find /I "IsntRunning.exe" > NUL
echo OUTSIDE_IF ERRORLEVEL %ERRORLEVEL%

@echo on

Putting that in a batch file and running it produces this output:

C:\Users\username\Documents\work>test.bat

OUTSIDE_IF 1

'ThisWillSetErrorLevelTo9009ieNotRecognizedCommand' is not recognized as an internal or external command, operable program or batch file.

OUTSIDE_IF 1

'ThisWillSetErrorLevelTo9009ieNotRecognizedCommand' is not recognized as an internal or external command, operable program or batch file.

INSIDE_IF ERRORLEVEL 9009

INSIDE_IF2 ERRORLEVEL GREQ 1 9009

OUTSIDE_IF ERRORLEVEL 1

Relevant articles:

  • http://blogs.msdn.com/b/oldnewthing/archive/2008/09/26/8965755.aspx
  • http://support.microsoft.com/kb/69576


Try using setlocal enabledelayedexpansion at the start of your batch file, and !ERRORLEVEL! inside your IF. This seems to work for me:

@echo off
setlocal enabledelayedexpansion
dir nul
echo %ERRORLEVEL%
if .1.==.1. (
  urklbkrlksdj - not a command
  echo %ERRORLEVEL%
  echo !ERRORLEVEL!
)


if errorlevel works without delayed expansion but works in manner similar to

if %errorlevel% <= Some_Value ... :

@echo off

::sets errorlevel to 0
(call )
if "1" == "1" (
    rem sets errorlevel to 5
    cmd /c exit 5
    if errorlevel 4 echo this will be printed
    if errorlevel 5 echo this will be printed
    rem :::: you can use this ::::::::::::::
    if errorlevel 5 if not errorlevel 6 echo this will be printed ONLY when the errorlevel is 5
    rem :::::::::::::::::::::::::::::::::::::
    if errorlevel 6 echo this will not be printed

)
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