I have created a basic Client Server that will send image files in a speci开发者_JAVA百科fied directory over a network. The code worked last week but I came back to it today and it seems that I am only getting one file on the server side, even though the client prints out that it has sent all the image files in the directory. It may be something in the client code but I think it is something on the server side. Any help is greatly appreciated and if you have a more efficient solution, I am happy to change my code as necessary. My code is below:
ImageServer
package com.encima.network.server;
import java.io.*;
import java.net.*;
public class ImageServer{
ServerSocket ss;
Socket s;
ObjectOutputStream oos;
int port = 4440;
public ImageServer() throws IOException {
try {
ss = new ServerSocket(port);
System.out.println("Server started on Port: " + port);
} catch(IOException e) {
System.out.println("Serevr: Port-" + port + " not available, exiting.");
System.exit(0);
}
System.out.println("Server: Waiting for Client Connection...");
while(true) {
try {
s = ss.accept();
new ImageHandler(s);
} catch (IOException e) {
e.printStackTrace();
}
}
}
public static void main(String[] args) throws IOException {
ImageServer is = new ImageServer();
}
}
ImageHandler
package com.encima.network.server;
import java.awt.image.BufferedImage;
import java.io.FileOutputStream;
import java.io.ObjectInputStream;
import java.net.Socket;
import javax.imageio.ImageIO;
public class ImageHandler implements Runnable {
Socket s;
int count = 0;
public ImageHandler(Socket socket) {
s = socket;
Thread t = new Thread(this);
t.start();
}
@Override
public void run() {
try {
ObjectInputStream ois = new ObjectInputStream(s.getInputStream());
FileOutputStream fos = new FileOutputStream("image" + System.nanoTime() + ".jpg");
count++;
//BufferedImage in = ImageIO.read(ois);
//ImageIO.write(in, "jpg", fos);
int ch = 0;
while(true) {
ch = ois.read();
if(ch == -1) {
break;
}
fos.write(ch);
}
fos.flush();
} catch (Exception e) {
e.printStackTrace();
}
}
}
Finally, the ImageClient
package com.encima.network.client;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.ObjectOutputStream;
import java.net.Socket;
import javax.imageio.ImageIO;
import com.encima.network.ImageFilter;
public class ImageClient {
Socket s;
String ip = "localhost";
int port = 4440;
ObjectOutputStream oos;
public ImageClient(File[] files) throws IOException, ClassNotFoundException, InterruptedException {
try {
s = new Socket(ip, port);
System.out.println("Client connected to Server via " + ip + " on port 80");
} catch (Exception e) {
System.out.println("Client: Cannot find Host: " + ip + ". Exiting.");
System.exit(0);
}
oos = new ObjectOutputStream(s.getOutputStream());
for(File f: files) {
sendFile(f);
}
oos.close();
//System.out.println("Written Image " + i + " of " + files.length);
}
public static void main(String[] args) throws IOException, ClassNotFoundException, InterruptedException {
File dir = new File("/Users/christophergwilliams/Dropbox/PhD/Projects/PhD/Year 1/GSN/images");
File[] files = dir.listFiles(new ImageFilter());
ImageClient ic = new ImageClient(files);
}
public void sendFile(File file) throws IOException {
FileInputStream fis = new FileInputStream(file);
//BufferedImage b = ImageIO.read(file);
//ImageIO.write(b, "jpg", oos);
int ch = 0;
while(true) {
ch = fis.read();
if(ch == -1) {
break;
}
oos.write(ch);
}
oos.flush();
System.out.println("Image Sent");
}
}
I am aware that it is a lot of code to read through but I do appreciate any help I can get on this!
I may be wrong but, for the sake of efficiency and network traffic, would it be beneficial to send the images as a zip from the client to the server?
Why are you using ObjectInputStream
at all? You're not reading or writing any serialized objects - just raw binary data. Use whatever InputStream
is provided, and read from that.
Anyway, that's not the big problem. The big problem is that you're just writing several files to one stream, with no indication of where one file is meant to finish and the next one is meant to start. How were you expecting to split the multiple files up? Options:
- Use a delimiter between files (very ugly - you'd have to potentially escape any data which looked like the delimiter as you went along)
- Prefix each file with its length
- Send each file on a different connection
(You're also reading and writing a single byte at a time. Use the overloads of read/write which accept byte arrays.)
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