How can I calculate the days between 1 Jan 2010 and (for example) 3 Feb 2010?开发者_Python百科
NSDate *date1 = [NSDate dateWithString:@"2010-01-01 00:00:00 +0000"];
NSDate *date2 = [NSDate dateWithString:@"2010-02-03 00:00:00 +0000"];
NSTimeInterval secondsBetween = [date2 timeIntervalSinceDate:date1];
int numberOfDays = secondsBetween / 86400;
NSLog(@"There are %d days in between the two dates.", numberOfDays);
EDIT:
Remember, NSDate
objects represent exact moments of time, they do not have any associated time-zone information. When you convert a string to a date using e.g. an NSDateFormatter
, the NSDateFormatter
converts the time from the configured timezone. Therefore, the number of seconds between two NSDate
objects will always be time-zone-agnostic.
Furthermore, this documentation specifies that Cocoa's implementation of time does not account for leap seconds, so if you require such accuracy, you will need to roll your own implementation.
You may want to use something like this:
NSDateComponents *components;
NSInteger days;
components = [[NSCalendar currentCalendar] components: NSDayCalendarUnit
fromDate: startDate toDate: endDate options: 0];
days = [components day];
I believe this method accounts for situations such as dates that span a change in daylight savings.
NSTimeInterval diff = [date2 timeIntervalSinceDate:date1]; // in seconds
where date1
and date2
are NSDate
's.
Also, note the definition of NSTimeInterval
:
typedef double NSTimeInterval;
Checkout this out. It takes care of daylight saving , leap year as it used iOS calendar to calculate.You can change the string and conditions to includes minutes with hours and days.
+(NSString*)remaningTime:(NSDate*)startDate endDate:(NSDate*)endDate
{
NSDateComponents *components;
NSInteger days;
NSInteger hour;
NSInteger minutes;
NSString *durationString;
components = [[NSCalendar currentCalendar] components: NSCalendarUnitDay|NSCalendarUnitHour|NSCalendarUnitMinute fromDate: startDate toDate: endDate options: 0];
days = [components day];
hour = [components hour];
minutes = [components minute];
if(days>0)
{
if(days>1)
durationString=[NSString stringWithFormat:@"%d days",days];
else
durationString=[NSString stringWithFormat:@"%d day",days];
return durationString;
}
if(hour>0)
{
if(hour>1)
durationString=[NSString stringWithFormat:@"%d hours",hour];
else
durationString=[NSString stringWithFormat:@"%d hour",hour];
return durationString;
}
if(minutes>0)
{
if(minutes>1)
durationString = [NSString stringWithFormat:@"%d minutes",minutes];
else
durationString = [NSString stringWithFormat:@"%d minute",minutes];
return durationString;
}
return @"";
}
With Swift 5 and iOS 12, according to your needs, you may use one of the two following ways to find the difference between two dates in days.
#1. Using Calendar
's dateComponents(_:from:to:)
method
import Foundation
let calendar = Calendar.current
let startDate = calendar.date(from: DateComponents(year: 2010, month: 11, day: 22))!
let endDate = calendar.date(from: DateComponents(year: 2015, month: 5, day: 1))!
let dateComponents = calendar.dateComponents([Calendar.Component.day], from: startDate, to: endDate)
print(dateComponents) // prints: day: 1621 isLeapMonth: false
print(String(describing: dateComponents.day)) // prints: Optional(1621)
#2. Using DateComponentsFormatter
's string(from:to:)
method
import Foundation
let calendar = Calendar.current
let startDate = calendar.date(from: DateComponents(year: 2010, month: 11, day: 22))!
let endDate = calendar.date(from: DateComponents(year: 2015, month: 5, day: 1))!
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .full
formatter.allowedUnits = [NSCalendar.Unit.day]
let elapsedTime = formatter.string(from: startDate, to: endDate)
print(String(describing: elapsedTime)) // prints: Optional("1,621 days")
Swift 4
Try this and see (date range with String):
// Start & End date string
let startingAt = "01/01/2018"
let endingAt = "08/03/2018"
// Sample date formatter
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "dd/MM/yyyy"
// start and end date object from string dates
var startDate = dateFormatter.date(from: startingAt) ?? Date()
let endDate = dateFormatter.date(from: endingAt) ?? Date()
// Actual operational logic
var dateRange: [String] = []
while startDate <= endDate {
let stringDate = dateFormatter.string(from: startDate)
startDate = Calendar.current.date(byAdding: .day, value: 1, to: startDate) ?? Date()
dateRange.append(stringDate)
}
print("Resulting Array - \(dateRange)")
Swift 3
var date1 = Date(string: "2010-01-01 00:00:00 +0000")
var date2 = Date(string: "2010-02-03 00:00:00 +0000")
var secondsBetween: TimeInterval = date2.timeIntervalSince(date1)
var numberOfDays: Int = secondsBetween / 86400
print(numberOfDays)
If you want all the units, not just the biggest one, use one of these 2 methods (based on @Ankish's answer):
Example output: 28 D | 23 H | 59 M | 59 S
+ (NSString *) remaningTime:(NSDate *)startDate endDate:(NSDate *)endDate
{
NSCalendarUnit units = NSCalendarUnitDay | NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond;
NSDateComponents *components = [[NSCalendar currentCalendar] components:units fromDate: startDate toDate: endDate options: 0];
return [NSString stringWithFormat:@"%ti D | %ti H | %ti M | %ti S", [components day], [components hour], [components minute], [components second]];
}
+ (NSString *) timeFromNowUntil:(NSDate *)endDate
{
return [self remaningTime:[NSDate date] endDate:endDate];
}
You can find the difference by converting the date in seconds and take time interval since 1970 for this and then you can find the difference between two dates.
To find the difference, you need to get the current date and the date in the future. In the following case, I used 2 days for an example of the future date. Calculated by:
2 days
* 24 hours
* 60 minutes
* 60 seconds
. We expect the number of seconds in 2 days to be 172,800.
// Set the current and future date
let now = Date()
let nowPlus2Days = Date(timeInterval: 2*24*60*60, since: now)
// Get the number of seconds between these two dates
let secondsInterval = DateInterval(start: now, end: nowPlus2Days).duration
print(secondsInterval) // 172800.0
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