Passing file args in a bash

The bash script is supposed to do one and one thing; ie; feeding the list of file names one after the other separated by a space to the jar file.

Here is part of the script

for(i=1;i<=5;i++) do
java <myjar.jar>file$i
done

what i expect the java <myjar.jar> file$i line to look like while executing the script is

java <myjar.jar> file1 file2 file3 file4 file开发者_开发技巧5

any help? Thanks!

---

Since it's bash, just do this:

java <myjar.jar> file{1..5}

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One way to do this might be to leverage the automatic shell filename expansion:

java myjar.jar file[1-5]

The above assumes that the files exist in the filesystem beforehand. Or, you can do something like:

java myjar.jar `for i in 1 2 3 4 5; do echo file$i; done`

If you have a large number of items, the seq command will help:

java myjar.jar `for i in $(seq 500); do echo file$i; done`

---

#!/bin/bash
declare -a listn
for n in $(seq $2 $3) ; do
    listn=("${listn[@]}" $n)
done

java "$1" "${listn[@]}"

And call the script with three arguments:

./the_script myjar.jar 1 5

The first argument is your jar name, the next is the first number in your sequence, the last is the final number.